七年级愉快的暑假数学 42页
信息发布者:20160628
1.
(1)∠BOC=90°+1/2∠BAC
∵∠BOC = 180° -∠OBC -∠OCB (三角形内角和为180°)
∵O是△ABC的三条角平分线的交点
∴∠OBC = 1/2∠ABC,∠OCB = 1/2∠ACB
∴∠BOC = 180°-1/2∠ABC -1/2∠ACB = 180° -1/2(∠ABC+∠ACB)
∵∠ABC + ∠ACB = 180°-∠BAC(三角形内角和为180°)
∵∠BOC = 180°-1/2(180°-∠BAC) = 90° +1/2∠BAC
(2) ∠DOB = ∠GOC
∵∠DOB = ∠ABO+∠BAO (三角形一个外角 = 另两个内角的和)
∴∠DOB =1/2∠ABC+ 1/2∠BAC=1/2(∠ABC+∠BAC)
=1/2 (180°-∠ACB)
= 90° -1/2∠ACB
= 90° -∠OCG
∵∠GOC = 180° -90° -∠OCG=90° -∠OCG
∴ ∠DOB = ∠GOC
2.
∵AB∥CD
∴∠2=∠3
∴∠1=∠4
即∠1=45° |
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